Answer:
74.15
Step-by-step explanation:
this is bc there are ten spaces between 74.1 and 74.2. halfway between that is another 00.05 points.
Answer:
Step-by-step explanation:Solve for y and replace with f−1(x) f - 1 ( x )
Answer:
y=x+3
(0,3)(1,4)
y=x+2
(0,2)(1,3)
Step-by-step explanation:
- For Y=X+3 it could be any point for Y as long as X is 3 less than Y.
- For Y=X+3 it could be any point for X and long as Y is 3 more than X.
- For Y=X+2 it could be any point for Y as long as X is 2 less than Y.
- For Y=X+2 it could be any point for X and long as Y is 2 more than X.
Answer:
the probability that the sample mean will be larger than 1224 is 0.0082
Step-by-step explanation:
Given that:
The SAT scores have an average of 1200
with a standard deviation of 60
also; a sample of 36 scores is selected
The objective is to determine the probability that the sample mean will be larger than 1224
Assuming X to be the random variable that represents the SAT score of each student.
This implies that ;

the probability that the sample mean will be larger than 1224 will now be:






From Excel Table ; Using the formula (=NORMDIST(2.4))
P(\overline X > 1224) = 1 - 0.9918
P(\overline X > 1224) = 0.0082
Hence; the probability that the sample mean will be larger than 1224 is 0.0082
2/21, 16/28
Multiply by 2,3,4