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fenix001 [56]
3 years ago
10

cathodic protection of iron involves using another more reactive metal as a sacrificial anode. classify each of the following me

tals by whether they would or would not act as a sacrificial anode to iron.
Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
6 0
The ones that would be sacrificial are; K, Na, Ca, Mg, Al, C, Zn
You might be interested in
What is the molar mass for a gas that effuses 0.344 times as fast as hydrogen gas?
Leona [35]
Rate of effusion gas/rate of effusion H2   =    √(M(H2))/√(M(gas))
0.344= √2/√(M(gas))
√(M(gas))= √2/0.344
M(gas)= (√2/0.344)² =2/(0.344)² ≈16.9
3 0
4 years ago
When you count up the electrons in a Lewis Structure, do double and triple bonds count as 4 or 6 electrons?
natima [27]

Answer:

Double=4 and triple=6

Explanation:

This is because double bonds are two pairs of electrons are shared between atoms and triple bonds are three pairs, and one pair of electrons is 2, so 2 x 2=4 and 2 x 3=6.

6 0
3 years ago
What mass of magnisium bromide is formed when 1.00 g of Mg + br
ella [17]

Mass of  Magnesium bromide : 5.76 g

<h3>Further explanation</h3>

Complete question

<em>What mass of  Magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?</em>

<em />

Reaction

<em />\tt Mg+Br_2\rightarrow MgBr_2<em />

mol Mg

\tt \dfrac{1}{24}=0.042

mol Br₂

\tt \dfrac{5}{160}=0.0313

Limiting reactants : Br₂(smaller)

mol MgBr₂ = mol Br₂=0.0313

mass MgBr₂ :

\tt 0.0313\times 184,113 =5.76~g

5 0
4 years ago
Construction crews sometimes use this reaction for welding underwater structures:
meriva

Answer:

5 moles of iron formed

Explanation:

Given data:

Moles of iron formed = ?

Moles of iron oxide react = 2.50 mol

Solution:

Chemical equation:

Fe₂O₃ + 2Al     →     Al₂O₃ + 2Fe

Now we will compare the moles of iron with iron oxide.

                  Fe₂O₃        :           Fe

                      1             ;            2

                  2.50          :          2×2.50 = 5 mol    

5 0
3 years ago
The nitrogen oxide (NO) molecule has a bond length of 140 pm. Calculate the dipole moment, in Debyes, that results if the charge
Cloud [144]

Answer:

Explanation:

Dipole moment = charge x separation of charges

= (2 x 1.6 x 10⁻¹⁹ ) x ( 140 x 10⁻¹² ) coulomb-metre

= 448 x 10⁻³¹coulomb-metre

1 debye = 3.33 x 10⁻³⁰coulomb-metre

Dipole moment in debye =  448 x10⁻³¹ / 3.33 x 10⁻³⁰debye

= 448 x10⁻³¹ / 33.3 x 10⁻³¹

= 13.45 debye

=

6 0
3 years ago
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