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3 years ago

Given the unbalanced equation below, how many moles

Chemistry

1 answer:

Svet_ta [14]3 years ago

8 0

Answer: 6 mol Li

Explanation:

The first step is to balance the equation.

2Li+Cl₂⇒2LiCl

We would need our conversions to find the amount of moles of Li needed to produces 6 mol LiCl.

$6molLiCl*\frac{2molLi}{2molLiCl} =6molLi$

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density.

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3 years ago

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vlabodo [156]

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3 years ago

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allochka39001 [22]

Answer:

$\large \boxed{\text{0.1767 mol/L}}$$

Explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O

(b) Moles of NaOH

$\text{Moles of NaOH} = \text{34.52 mL NaOH} \times \dfrac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}$

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

$\text{Moles of H$_{3}$PO}_{4} = \text{13.26 mmol NaOH} \times\dfrac{\text{ 1 mmol H$_{3}$PO}_{4}}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H$_{3}$PO}_{4}$

(d) Molar concentration of H₃PO₄

$c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V} = \dfrac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol $\cdot$ L$^{-1}$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{0.1767 mol/L}}$}$

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3 years ago