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bonufazy [111]
3 years ago
13

In Exercises 21-26, a fair coin is tossed two times in succession.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer: I need more context

Step-by-step explanation:

You might be interested in
Hurry 50 points for correct answer
Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation x=\sqrt{6x+7} can be solved by squaring both sides:

x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

1 = \sqrt{-1}\\ 7 = \sqrt{49}

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

4 0
3 years ago
If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
3 years ago
I don’t know number 20
makkiz [27]

the answer is 25 because it’s going up by 5s

7 0
3 years ago
Read 2 more answers
Can i please get help on this Question?
Vladimir79 [104]

i would say the answer is 17  because i used the calculator

3 0
3 years ago
What is equivalent to (3 root 8^1/4 x) ?
vfiekz [6]

Answer:

The given expression is equivalent to 3(2^(3/8))x.

Step-by-step explanation:

The given expression (3 root 8^1/4 x) can be written as:

3√(8^(1/4))x

we know that 2^3 = 8

= 3√(2^(3/4))x

We know that √x = (x)^(1/2)

= 3(2^((3/4)(1/2))x

Powers multiply with each other, 3*1/4*2 = 3/8

= 3(2^(3/8))x

7 0
3 years ago
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