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2 years ago

9

Can you help me please

1 answer:

horsena [70]2 years ago

4 0

Answer:

zero slope

Step-by-step explanation:

its not goin up or down so there is no slope:)

also look below :)

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What is the midpoint of (2,-2,4) and (-2,0,6)

Mekhanik [1.2K]

Midpoint of (a,b,c) and (e,f,g) is
((a+e)/2,(b+f)/2,(c+g)/2)
just average them

the x value
(2+-2)/2=0/2=0

the y value
(-2+0)/2=-2/2=-1

the z value
(4+6)/2=10/2=5

(0,-1,5) is da midopint

6 0

3 years ago

Nataly_w [17]

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4 0

2 years ago

Find the radius of convergence, then determine the interval of convergence

galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.

First aₙ is noted and then aₙ₊₁ is noted.

For ∑ aₙ, aₙ and aₙ₊₁ is noted.

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = β

If β < 1, then the series converges

If β > 1, then the series diverges

If β = 1, then the series inconclusive

Here $a_{k}$ = $\frac{(x+2)^{k}}{\sqrt{k} }$ and $a_{k+1}$ = $\frac{(x+2)^{k+1}}{\sqrt{k+1} }$

Now limit is taken,

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|$

= $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|$

= $\lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|$

= $|{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}$

= $|{x+2 }|$ < 1

- 1 < ${x+2 }$ < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

#SPJ1

5 0

1 year ago

Read 2 more answers

What is 1,000=850+0.2p

katen-ka-za [31]

Heyy thanks for you question you answer would be P=750
Hope this helps!!

4 0

3 years ago

Find area of a parallelogram with a height of 8 inches and a base of 14 inches

12345 [234]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{112 \: {inches} \: ^{2} }}}}}$

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

<u>Finding </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>parallelogram</u>

<u> $\boxed{ \sf{area \: of \: parallelogram \: = \: base \: \times \: height}}$ </u>

⇒<u> $\sf{area \: of \: parallelogram \: = \: 14 \: \times 8}$ </u>

⇒<u> $\sf{area \: of \: parallelogram = 112 \: {inches}^{2} }$ </u>

Hope I helped!

Best regards! :D

4 0

3 years ago