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3 years ago

How do you calculate tan^-1 (10/53)

Mathematics

1 answer:

frez [133]3 years ago

5 0

Answer:

Use you calculator.

Step-by-step explanation:

There will be a way on your calculator to do tan^-1. It may be called arctan. They are the same thing.

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Addie bought lunch to go from a sandwich shop. She spent $12.00 for a $10.00 meal. What percent was the tip?

horsena [70]

Answer:

She gave a $2.00 tip witch would be %20 of her meal cost.

Step-by-step explanation:

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3 years ago

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How do you write (6)^-2 without exponents?

m_a_m_a [10]

(6)^-2 Is equivalent to 1/36

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3 years ago

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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago

A water tower casts a 100-foot shadow. At the same time, an 8-foot stri

bogdanovich [222]

Set up ratios of height / shadow length:

8/6 = x/100

Cross multiply

6x = 800

Divide both sides by 6

X = 133.33 feet

The tower is 133.3 feet

6 0

3 years ago

Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

Substitute in x: g'(0) = 10sin(0)
Evaluate Trig: g'(0) = 10(0)
Multiply: g'(0) = 0

3 0

3 years ago