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3 years ago

A student is selling small and large frozen pizzas for a school fund-raiser.

Mathematics

1 answer:

dexar [7]3 years ago

6 0

System of equations:

We'll need one equation for the amount of pizzas, and another for the total cost of the pizzas. In this case, x will represent small pizzas, and y will represent large pizzas.

3x + 4y = 100

x + y = 30

Solving the system of equations:

First, we need to solve for one variable in one equation.

x + y = 30

x = 30 - y

Then, we'll take our equation that is solved for x and plug it into the other equation from above.

3(30 - y) + 4y = 100

Next, we solve for y.

90 - 3y + 4y = 100

90 + y = 100

y = 10

Finally, we take our value for y and plug it back in to the very first equation and solve for x.

x = 30 - 10

x = 20

Answer:

The student has sold 10 large pizzas and 20 small pizzas.

Hope this helps!! :)

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Angle Side Angle Theorem (ASA)

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3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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3 years ago

The figure shows a parallelogram inside a rectangle outline: A parallelogram is shown within a rectangle. The length of the rect

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Step-by-step explanation:

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3 years ago

1. Simplifying Equation Below please help!!

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3 years ago

Read 2 more answers

Three coins are flipped.

Darina [25.2K]

Step-by-step explanation:

when 3 coins are flipped the following outcomes are possible

h = heads, t = tails

h h h

h h t

h t h

h t t

t h h

t h t

t t h

t t t

yes, there have to be 8 options, because we have 3 positions with 2 possible outcomes. that means

2×2×2 = 2³ = 8 possibilities.

at least 2 tails means 2 or 3 t in the list item :

h t t

t h t

t t h

t t t

so, 4 out of the 8 possible outcomes. the probability is then therefore

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2 years ago