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Reptile [31]
3 years ago
9

George is required to produce 500 frames for an art gallery. He spent $100 on the wood required for all these frames. He also sp

ent $50 in polishing all the final frames. He rented two floors of an art gallery for about $700. What selling price should George charge the art gallery if he wants to break even?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

George should charge 1.70$ for each frame to break-even.

Step-by-step explanation:

Variable cost for the frames:

Wood + polishing = $100 + $50 = $150

Variable cost per frame would be:

$150/ 500 = $0.30

The fixed cost of the operation is $700.

George has to make 500 frames.

Fixed cost / (Selling price per unit – variable cost per unit) = 500

$700 / (Selling price per unit - $0.30) = 500

700 = 500 (Selling price per unit – 0.30)

700 = 500 * Selling price – 500 * 0.3

700 = 500 * Selling price – 150

(700 + 150) / 500 = Selling price

850 / 500 = 1.7

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Please help! (Also show work)<br> Tutorials :D
oksano4ka [1.4K]

The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

<h3>How to Find the Five-number Summary of a Data?</h3>

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

  • Minimum value: this is the smallest lengths, which is 9
  • First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.
  • Median: the median is the center of the data distribution which is 25.5.
  • Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.
  • Maximum: this is the largest length in minutes, which is, 51.

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

Learn more about the five-number summary on:

brainly.com/question/24809873

#SPJ1

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