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Murrr4er [49]
3 years ago
13

8. Show work here for 5(3d+5e+3)

Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer:

15d+25e+15

Step-by-step explanation:

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Find S11 for 1 + 2 + 4 + 8 +
Free_Kalibri [48]
Evaluating the given sequence, it is evident that the next number is twice the number prior to it. Thus, the given is a geometric sequence with first term (a1) equal to 1 and common ratio of 2. The geometric series may be calculated by the equation,
 
                                            Sn = a1 x (1 - r^n) / (1 - r)

where Sn is the sum of n terms in this case, n = 11. 
Substituting the known values, 
 
<span>                                      Sn = 1 x (1 - 2^11) / (1 - 2) = 2047
</span>
Thus, S11 is 2047. 
4 0
4 years ago
Subtract and simplify 1/2-1/3
frez [133]
It’s gonna be 1/6 for this question!
4 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST
puteri [66]

Answer:

22.5

Step-by-step explanation:

You just have to do 60 divided by 2.66   (The decimal form of 2/3) and then you have your answer PLEASE BRAINLIEST

5 0
3 years ago
Read 2 more answers
Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression −4(6)n − 1.
Verizon [17]

Answer:

<h2>-223,948</h2>

Step-by-step explanation:

The formula of a sum of terms of a gometric sequence:

S_n=a_1\cdot\dfrac{1-r^n}{1-r}

a₁ - first term

r - common ratio

We have

a_n=-4(6)^{n-1}

Calculate a₁. Put n = 1:

a_1=-4(6)^{1-1}=-4(6)^0=-4(1)=-4

Calculate the common ratio:

r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=-4(6)^{n+1-1}=-4(6)^n\\\\r=\dfrac{-4(6)^n}{-4(6)^{n-1}}=6^n:6^{n-1}\\\\\text{use}\ a^n:a^m=a^{n-m}\\\\r=6^{n-(n-1)}=6^{n-n+1}=6^1=6

\text{Substitute}\ a_1=-4,\ n=7,\ r=6:\\\\S_7=-4\cdot\dfrac{1-6^7}{1-6}=-4\cdot\dfrac{1-279936}{-5}=-4\cdot\dfrac{-279935}{-5}=(-4)(55987)\\\\S_7=-223948

7 0
4 years ago
Find the difference of the two expressions. (2/3+2)−(1/3−4)<br> •−2<br> •+6<br> •1/3−2<br> •1/3+6
vampirchik [111]
The answer is D , 1/3+6 .
6 0
3 years ago
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