3 years ago

8. Show work here for 5(3d+5e+3)

Mathematics

1 answer:

Darya [45]3 years ago

4 0

Answer:

15d+25e+15

Step-by-step explanation:

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9/100 in simplest form?

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You can also say that 9/100=0.09

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Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger

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Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for x as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of x is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of x is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

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