To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are
From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u
Thus, the required Mass Defect is 0.5634u.
In eV, the Mass Defect is 
Answer:
m∠2 = 78°
Step-by-step explanation:
From the given picture,
lines 'm' and 'n' are the parallel lines and line 't' is the transverse line.
∠1 and angle with the measure of 78° are corresponding angles.
Therefore, m∠1 = 78°
m∠1 = m∠2 [Vertical angles are equal]
m∠2 = 78°
Answer:
of evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seisof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesmic waves heat flow in meteorites
Step-by-step explanation:
of evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteoritesof evidence from seismic waves heat flow in meteorites
3/4 divides by 1/7 =
copy dot flip
3/4 * 7/1
21/4
4 goes into 21 5 times with 1 left over
5 1/4
Answer:
1/4
Step-by-step explanation:
p% = p/100 so that
25/100 then after we will reduce both with 25
1/4
