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luda_lava [24]
3 years ago
8

To rent some equipment from a local hardware store, it costs $65 for 8 hours. To rent it for 12 hours, it costs $85. If the rate

of change is constant, find the rate of change (cost per hour).
Mathematics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

it costs 7-8$ per hour

Step-by-step explanation:

the answer is estimated

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What is the range of function g if g (x) = f(x) + 3?
masya89 [10]
I think it is D, hope it helps
7 0
2 years ago
Which statement correctly compares the spreads of the distributions?
Pavlova-9 [17]

Answer:

Step-by-step explanation:

Mode definition is the number which appears most often in a set of numbers.  Since the mode is the same amount of bubbles it is not A.

The range of a set of data is the difference between the highest and lowest values in the set.

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

The data has already been ordered for you so you take the highest number and subtract the smallest number.  

Cityview Zoo  44-37=7

Countryside Zoo  45-38=7

6 0
3 years ago
Read 2 more answers
Please answerrrr, its not that hard i dont think lol, i j dont know it :)
dlinn [17]

Not a function.

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6 0
3 years ago
By what percent will a fraction decrease if its numerator is decreased by 85% and its denominator is decreased by 25%??
belka [17]

Answer:

106.67%

Step-by-step explanation:

85% as a fraction is 4/5

25% as a fraction is 3/4

<h2>\frac{4}{5}/\frac{3}{4}=\frac{16}{15} </h2>

Convert 16/15 to a decimal: 1.067

Multiply: 1.067 · 100= 106.67%

4 0
3 years ago
3x-(2x-1)=7x-(3*5x)+(-x+24)
Paraphin [41]

Answer:

\boxed{\boxed{\sf x=\frac{23}{10}}\: \sf or \:\boxed{x=2.3}}

_________________

\boxed{\sf Step\: By\:Step:- }

\sf 3x-\left(2x-1\right)=7x-\left(3\times \:5x\right)+\left(-x+24\right)

<u>Remove the parentheses:</u>

\to\sf 3x-\left(2x-1\right)=7x-3\times \:5x-x+24

<u>Combine like terms:</u>

\sf ^*7x-x=6x

\to\sf 3x-\left(2x-1\right)=6x-3\times \:5x+24

<u>Multiply 3 and 5x = 15x:-</u>

\to\sf 3x-\left(2x-1\right)=6x-15x+24

<u>Combine like terms:</u>

\sf ^*6x-15x=-9x

\to\sf 3x-\left(2x-1\right)=-9x+24

<u>Expand: 3x-(2x-1)= x+1</u>

\to\sf x+1=-9x+24

<u>Subtract 1 from both sides:</u>

\to\sf x+1-1=-9x+24-1

\to\sf x=-9x+23

<u>Add 9x to both sides:</u>

\to\sf x+9x=-9x+23+9x

\to\sf 10x=23

<u>Divide both sides by 10:</u>

\to\sf \cfrac{10x}{10}=\cfrac{23}{10}

\to\sf x=\cfrac{23}{10}

<u>________________________________</u>

3 0
3 years ago
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