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Mumz [18]
3 years ago
10

Solve the equation: 315= 390- 25q ​

Mathematics
2 answers:
Lena [83]3 years ago
7 0

Answer: q = 3

Step-by-step explanation:

315 = 390 - 25Q  

1. Minus 390 from both sides

-75 = =-25q

2. Divde both sides by -25 to get q by itself

3 = q or  q = 3

RoseWind [281]3 years ago
4 0

Answer:

q=3

Step-by-step explanation:

315=390-25q

390-25q=315

390-25q-390=315-390

-25q=-75

Divide both sides by 25

q=3

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kompoz [17]

Answer:

Step-by-step explanation:

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7 0
3 years ago
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Please i need help ASAP!!!​
Mamont248 [21]
The answer is 10^4
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5 0
2 years ago
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Write an equation that passes through (2,4) is parallel to the line 3x-2y=-10
vodomira [7]

Answer:

y = 3x/2 + 3

Step-by-step explanation:

First let's solve for y in the given equation

Subtract 3x from both sides

3x - 2y = -10

- 3x         - 3x

-2y = -3x - 10

Divde both sides by -2

-2y/-2 = (-3x - 10)/-2

y = 3x/2 + 5

The slop of the parallel equation will have to be 3/2

y = 3x/2 + b

Plug in the given coordinates

4 = 3(2)/2 + b

4 = 1 + b

Subtract 1 from both sides

4 = 1 + b

- 1.  - 1

b = 3

y = 3x/2 + 3

7 0
3 years ago
The answer please. (F-g)(-3)
ad-work [718]
There are two ways to do this
Method 1:

Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1

Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38

-----------------------------------------

Method 2:

Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48

Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10

Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38

-----------------------------------------

Whichever method you pick, the answer is: 38

4 0
4 years ago
What is the difference?
Ganezh [65]

Answer:

\frac{x^2+4x-1}{x(x+2)}

Step-by-step explanation:

Given

\frac{x+5}{x+2} - \frac{x+1}{x^2+2x} ← factor denominator

= \frac{x+5}{x+2} - \frac{x+1}{x(x+2)}

We require the fractions to have a common denominator.

Multiply numerator/denominator of first fraction by x

= \frac{x(x+5)}{x(x+2)} - \frac{x+1}{x(x+2)}

Subtract terms on numerator leaving the common denominator

= \frac{x^2+5x-x-1}{x(x+2)}

= \frac{x^2+4x-1}{x(x+2)}

7 0
3 years ago
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