Answer:
D
Step-by-step explanation:
Answer:
$3
Step-by-step explanation:
The money shared by Ben and Carol was split ...
... Ben : Carol = 1 : 3
The difference of these ratio numbers is 2, and the difference in amount received is $6. Thus, each ratio unit must stand for $6/2 = $3.
... Ben received 1×$3 = $3
_____
<em>The Rest of the Story</em>
Carol received 3×$3 = $9. Together, Ben and Carol received $3 + 9 = $12, which is 4/5 of the total amount. Then the 1/5 of the total amount that Alice received is
... (1/5)×$12/(4/5) = (1/4)×$12 = $3.
The $15 of money was split ...
... Alice : Ben : Carol = $3 : $3 : $9
(-5x ⁵+14)-(11x ²+1+11x ⁵)
Like terms: -5x ⁵-11x ⁵ = -16x ⁵
Like terms also: 14-1 = 13
Simplified all together: -16x ⁵ - 11x ²+ 13
(Always put highest degree first)
Answer:
Step-by-step explanation:
<h3>Solving linear equation with one variable:</h3>
1) -4 + 3x = 4x - 8
Add 4 to both sides
-4 + 3x + 4 = 4x - 8 + 4
3x = 4x - 4
Subtract 4x from both sides,
3x - 4x = -4x + 4x - 4
-x = -4

2) -5x - 8 = 2
Add 8 to both sides
-5x - 8 + 8 = 2 + 8
-5x = 10
Divide both sides by (-5)


3) 12r - 14 = 5(2-r)
12r - 14 = 5*2 - 5*r
12r - 14 = 10 - 5r
Add 14 to both sides
12r - 14 + 14 = 10 - 5r + 14
12r = 24 - 5r
Add 5r to both sides
12r + 5r = 24
17r = 24
Divide both sides by 17
r = 24/17
4) 3x - 8 = -(17 + 2x)
3x - 8 = -17 - 2x
Add 8 to both sides
3x - 8 + 8 = -17 - 2x + 8
3x = -9 - 2x
Add 2x to both sides
3x + 2x = -9
5x = -9
Divide both sides by 5
