Answer:
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Step-by-step explanation:
Given:
AD ≅ BC and AD || BC
To Prove:
ABCD is a Parallelogram
Proof:
Alternate Interior Angles Theorem :
"When two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.
Here AD || BC and the transversal is AC
Statement Reasons
1. AD ≅ BC . 1. Given
2. AD || BC 2. Given
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Answer:
¶Emma Jess¶
Step-by-step explanation:
,
Dont ask me why...I cant really explain it...but if u have 1 repeating decimal, u put it over 9. If u have 2 repeating decimals, u put it over 99....3 repeating decimals, put it over 999.
Examples :
0.7 (repeating) = 7/9
0.27 (repeating) = 27/99 when simplified = 3/11 <===
0.444 (repeating = 444/999
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
