All categories

2 years ago

PLEASE HELP!!!!!!

Mathematics

2 answers:

Sholpan [36]2 years ago

8 0

A: High School P, because it has the lowest <span>σ
B: High School N, because it has the highest mean</span>

IRINA_888 [86]2 years ago

6 0

Answer:

High School P has the most consistent attendance among its students.

School N should be awarded for the highest average attendance.

Step-by-step explanation:

Consider the provided information.

Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically.

Standard deviation (σ) is a measure of how a data set is spread out.

If the standard deviation is low, this implies that the information tends to be near to the set mean, whereas a high standard deviation implies that the information points are spread across a wider spectrum of values.

Therefore, for more consistency we need to look for the low standard deviation.

From the provided table we can see that the school P has low standard deviation (σ) i.e 31.5

Hence, High School P has the most consistent attendance among its students.

Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically.

The formula for mean is:

$Mean=\frac{x_1+x_2+...+x_n}{n}$

Mean is the same as average.

The sum of mean or average will be larger if each students contributes more attendance.

For highest average attendance the school with higher mean should be awarded.

Hence, School N should be awarded for the highest average attendance.

You might be interested in

a box of crackers has a volume of 48 cubic inches. what is the volume of a similar box that is smaller by a scale factor of 2/3

earnstyle [38]

For this case what you need to know is that the original volume of the cookie box is:
V = (w) * (l) * (h)
Where,
w: width
l: long
h: height.
We have then:
V = (w) * (l) * (h) = 48 in ^ 3
The volume of a similar box is:
V = (w * (2/3)) * (l * (2/3)) * (h * (2/3))
We rewrite:
V = ((w) * (l) * (h)) * ((2/3) * (2/3) * (2/3))
V = (w) * (l) * (h) * ((2/3) ^ 3)
V = 48 * ((2/3) ^ 3)
V = 14.22222222 in ^ 3
Answer:
the volume of a similar box that is smaller by a scale factor of 2/3 is:
V = 14.22222222 in ^ 3

6 0

2 years ago

The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the

umka21 [38]

This is probably way overcomplicated but i cant remember how to do it
w = n
l = 2n+1
w*l = 66
n(2n+1) = 66
2n^2 + n =66
2n^2 + n - 66 = 0
using quadratic equation

n = 11/2

width = 11/2 = 5.5
length = 11 + 1 = 12

3 0

2 years ago

5. Find the squares of the following numbers by using the formula of (a + b)' or (a-b]². c) 98

Dmitrij [34]

98^2 = (100-2)^2

Using (a-b)^2, we have

= (100)^2-2(100)(2)+(2)^2

= 10000-400+4

= 10004-400

= 9604

The answer is 9604.

Please mark me Brainliest

5 0

2 years ago

Please help find the Measure of 1 step by step

maks197457 [2]

Answer: 112°

Step-by-step explanation:

a straight line only has 180° at all times so it is a matter of subtraction. 180-68 is 112° so from there you can find #2 as 68°, #3 as 90° and #4 as 90°, and so on.

3 0

2 years ago

Need help

aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by: