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Andre45 [30]
3 years ago
6

2/3< x/8 <7/8 what number could replace x to make a true statement 3 4 5 6

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Multiply all three sides by 8 to get x by itself

16/3 < x < 7

5 1/3 < x < 7

so it’s between 5 and 1/3 and 7. the only answer between those two would be 6. 3 and 4 is too less. 5 is also too less.

umka2103 [35]3 years ago
3 0
I think it could very well be 6
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Step-by-step explanation:

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Yearly expense of the in state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $3,500 + $8,400  = $11,900

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Lets calculate first for  out of state college

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Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

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Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

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