If f(z)=m^z - n^z <span>and f(1)=2, f(2)=8
then
m - n = 2 so m = n + 2
m^2 - n^2 = 8
substitute </span>m = n + 2 into m^2 - n^2 = 8
so
m^2 - n^2 = 8
(n + 2)^2 - n^2 = 8
n^2 + 4n + 4 - n^2 = 8
4n = 4
n = 1
m = n + 2 = 1 + 2 = 3
so f(z) = 3^z - 1^z
if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26
answer
f(3) = 26
Hope this helped the answer is in purple
Answer:
2cm x 2cm x 2cm
∛8=2
Step-by-step explanation:
2cm x 2cm x 2cm
∛8=2
They are all prime numbers
Area is 50 m^2
5 x 3 = 15
7 x 5 = 35
35 + 15 = 50 m^2
