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ziro4ka [17]
3 years ago
14

In the past month, Lashonda rented 7 video games and 1 DVD. The rental price for each video game was $2.90The rental price for t

he DVD was $3.50. What is the total amount that Lashonda spent on video game and DVD rentals in the past month
Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0
Video games : $20 and DVD $3.50 = $23.50
solniwko [45]3 years ago
4 0

Answer:

Lashonda spent $23.8 all together.

Step-by-step explanation:

We solve this by multiplying how many videogames she bought with how much they cost plus how much that one DVD cost.

7 x 2.90 + 3.50

This equals

23.8

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In frequency curve the points are joined by bits of a straight line. True/False​
pashok25 [27]
False. The frequency curve for a distribution can be obtained by drawing a smooth and free hand curve through the midpoints of the upper sides of the rectangles forming the histogram.
7 0
2 years ago
Question in picture solve
dimulka [17.4K]

Answer:

x= 13.5

Step-by-step explanation:

f(x) = 2x + 9

f(x) = 36

Set the 2 equations equal to each other;

2x + 9 = 36

Subtract 9 from both sides;

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Divide both sides by 2;

x = 13.5

<em>Check:</em>

f(x) = 2x + 9

f(13.5) = 2(13.5) + 9= 27 + 9 = 36

3 0
3 years ago
Out of 600 seniors at a local high school, 60% went on the senior trip. At the hotel, one room was reserved for every 4 students
butalik [34]

Given:

Total number of senior students = 600

60% went on the senior trip.

One room was reserved for every 4 students.

To find:

The total number of reserved rooms.

Solution:

60% went on the senior trip from total 600 students. So, number of students who went on tripe is

600\times \dfrac{60}{100}=360

Now, one room was reserved for every 4 students. So,

\text{Required number of rooms}=\dfrac{\text{Number of students who went on tripe}}{\text{Number of students in room}}

\text{Required number of rooms}=\dfrac{360}{4}

\text{Required number of rooms}=90

Therefore, the required number of reserved rooms were 90.

4 0
3 years ago
calculate the means and the standard deviation of the following set of data 4.578g, 4.581g, 4.572g, 4.573g, 4.601g, 4.577g. stat
AfilCa [17]

Answer:

68% Confidence interval  = [4.5752, 4.5848]

95% Confidence interval  = [4.5688, 4.5918]

Step-by-step explanation:

Sample mean (X) = 4.580

Sample Standard Deviation (S) = 0.01065

Sample size (n) = 6

T_{(5)} for alpha/2 0.84 = 1.1037

T_{(5)} for alpha/2 0.975 = 2.5706

68% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}] = [4.5752, 4.5848]

95% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}] = [4.5688, 4.5918]

7 0
3 years ago
6 quarts is how many fluid ounces​
fenix001 [56]

Answer:

its 192 fluid ounces

Step-by-step explanation:

8 0
3 years ago
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