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goldenfox [79]
3 years ago
8

Jada has read 35 of a book. She has read 75 pages so far. How many pages are in the whole book?

Mathematics
2 answers:
Savatey [412]3 years ago
6 0

Answer:

Im Guessing 110 for what info u just gave me.

Step-by-step explanation:

75+35 = 110

Kruka [31]3 years ago
3 0

Answer:

126

Step-by-step explanation:

Andre draws this tape diagram for 3 divided by 23:

Andre says that 3 divided by 23 = 413 because there are 4 groups of 23 and 13 left. Do you agree with

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542 L = kL help plzzzzzz
crimeas [40]

Answer:

0.542

Step-by-step explanation:

1 L = 0.001 Kiloliter and 542 x 0.001 = 0.542

6 0
3 years ago
|-14| = pls help lolololollolllololol
Vladimir79 [104]

Answer:14

Step-by-step explanation:

Well for the answer you just answer the opposite of the question

3 0
4 years ago
Read 2 more answers
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
Given 2 and 1 over 10 times negative seven times 5 over 12, determine the product.
yKpoI14uk [10]

The solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

<h3>How to Multiply Fractions?</h3>

2 and 1 over 10 times negative seven times 5 over 12 can also be expressed as; 2¹/₁₀ * ⁽⁻⁷ * ⁵⁾/₁₂

Multiplying out the bracket gives;

²¹/₁₀ * -³⁵/₁₂

Dividing by common factors gives;

= ⁷/₂ *  ⁻⁷/₄

= -49/8

= -6¹/₈

This can also be written as negative six and 1 over 8

Thus, we conclude that the solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

Read more about Multiplication of fractions at; brainly.com/question/7335118

#SPJ1

4 0
2 years ago
The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr
Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0
3 years ago
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