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Inessa05 [86]
3 years ago
5

Arrange the numbers as they appear from left to right on a horizontal number line. -2.76, 2.5, 2.85, -1.58, -1.85, -2.57, -2.5

Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer:

-2.76  -2.57  -2.5  -1.85 -1.58  2.5  2.85

   |           |         |        |        |       |        |

--------------------------------------------------------

-3                                            0                3

I hope this helped (not sure if I did it right) :D

Step by step explanation:

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Expand and simplify 2(a+3)+3(2a-1)
AlexFokin [52]
2(a+3)+3(2a-1)
=2a+6+6a-3
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7 0
3 years ago
Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left
Wewaii [24]
1/5 of 20 is $4. So, 20-4=$16 remaining.
3/8 of 16 is $7.50. So, 16-7.50= $8.50 remaining.
2/7 of 8.5 is $2.43. So, 8.50-2.43 is $6.07

Answer: Ken has $6.07 left after all his purchases.

6 0
3 years ago
Read 2 more answers
Brianna has x nickels and y pennies. She has no less than 20 coins worth no more
Bond [772]

Answer:

y \ge 20 - x

y \le 80 -5x

(x,y) = (15,5)

Step-by-step explanation:

Given

Nickels = x

Pennies = y

Amount = \$0.80 maximum

Coins = 20 minimum

Required

Solve graphically

First, we need to determine the inequalities of the system.

For number of coins, we have:

x\ +\ y\ge 20 because the number of coins is not less than 20

For the worth of coins, we have:

0.05x\ +\ 0.01y\ \le0.80 because the worth of coins is not more than 0.80

So, we have the following equations:

x\ +\ y\ge 20

0.05x\ +\ 0.01y\ \le0.80

Make y the subject in both cases:

y \ge 20 - x

0.01y \le 0.80 - 0.05x

Divide through by 0.01

\frac{0.01y}{0.01} \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}

y \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}

y \le 80 -5x

The resulting inequalities are:

y \ge 20 - x

y \le 80 -5x

The two inequalities are plotted on the graph as shown in the attachment.

y \ge 20 - x --- Blue

y \ge 80 -5x --- Green

Point A on the attachment are possible solutions

At A:

(x,y) = (15,5)

4 0
2 years ago
How to use the Pythagorean theorem to provee if a triangle with the side lengths 7,14,28 is a right triangle. Plz help
Lapatulllka [165]

Answer: find the answer in the explanation.

Step-by-step explanation:

To use the Pythagorean theorem to prove if a triangle with the side lengths 7,14,28 is a right triangle, you will square 7 and add it to the square of 14. The square root of the sum will be equal to 28 if it is a right angle triangle. Otherwise, it is not.

(7^2 + 14^2) = 49 + 196

245

Find the square root of 245

Square root = 15.65

Since it is not 24, the triangle is not a right angle triangle.

8 0
3 years ago
Can anyone help me with this. please​
zvonat [6]

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2+b^2=c^2

7^2+KL^2=25^2

49+KL^2=625

KL^2=625-49

KL=\sqrt{576

KL=24

take M as reference angle

using tan rule

tan M=/opposite/adjacent

tan M=KL/ML

tan M=24/7

5 0
3 years ago
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