Given data:
The diameter of the cut sphere, D=14 in.
The radius of the cut sphere is,

The cut sphere is called a hemisphere.
The surface area of a sphere is

So, the lateral surface area of a hemisphere is half the surface area of sphere. Therefore, the lateral surface area of a hemisphere is,

The hemisphere has a lateral surface and a circular surface. The area of the circular surface is,

Therefore, the total area of the hemisphere is,

The total surface area of a hemisphere is,

Therefore, the total surface area of the cut sphere is 461.8 square inches.
The attached image may have what you're looking for.
Step-by-step explanation:
2(x-3)=5(x-3)+10
=> 2x - 6 = 5x - 15 + 10
=> -6 + 15 -10 = 5x - 2x
=> 5x -2x = 15 - 6 - 10
=> 3x = 15 - 16
=> 3x = -1

We need to use Law of sine.
sin A/a = sin C/c
sin A/|CB| = sin C/|AB|
sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20
A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰