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Leviafan [203]
3 years ago
7

PLEASE HELPP!!! What is the sample space for flipping 4 fair coins?

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

16

Step-by-step explanation:

If you flip 4 coins there are 16 possible outcomes

You can determine this by doing 2^{x} x is 4 in this case

unless you want all the outcomes... I can answer that if you want

TTTT, TTTH, TTHT, THTT, HTTT, TTHH, THTH, HTHT, HHTT, THHT, HTTH, THHH, HTHH, HHTH, HHHT, HHHH

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Convert 9421mm to metres​
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9.421 meters

Step-by-step explanation:

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2 years ago
Plz help math
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The answer is B. 0.000000849

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Find the value of x.<br> 2x 1250<br> 160°<br> 110°<br> to<br> 147°<br> 112°<br> X =
erastova [34]

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Step-by-step explanation:

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3 years ago
Please help! I need this!
nirvana33 [79]

Answers:

Masuma - 30 seconds

Nashrah - 120 seconds

Harsha - 40 seconds

Explanation:

Masuma's finish time was half of Heathe's, so 60/2=30

It took Nashrah 4 times longer than Masuma to finish, so 30 x 4 = 120

Harsha was 3/4 of the way done when Masuma finished, so 30 = 3/4, meaning each 1/4 is equal to 10 seconds, making the finishing time 40 seconds.

Hope this helped!

7 0
3 years ago
9. A space probe near Neptune communicates with Earth using bit strings. Suppose that in its transmissions it sends a 1 one-thir
ollegr [7]

Answer:

a) 0.6667 = 66.67% probability that a 0 is received.

b) 0.9 = 90% probability that a 0 was transmitted, given that a 0 was received.

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

(a) Find the probability that a 0 is received.

0.9 of 2/3(0 received when a 0 is sent).

0.2 of 1/3(0 received when a 1 is sent). So

p = \frac{0.9*2}{3} + \frac{0.2*1}{3} = 0.6667

0.6667 = 66.67% probability that a 0 is received.

(b) Use Bayes theorem to find the probability that a 0 was transmitted, given that a 0 was received.

Event A: 0 received

Event B: 0 transmitted.

0.6667 = 66.67% probability that a 0 is received, which means that P(A) = 0.6667

A zero is transmitted two-thirds of time, which means that P(B) = 0.6667

When a 0 is sent, the probability that it is received correctly is 0.9, which means that P(B|A) = 0.9

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.6667*0.9}{0.6667} = 0.9

0.9 = 90% probability that a 0 was transmitted, given that a 0 was received.

3 0
3 years ago
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