The reference to the root of the tree should be set to null
<h3>Can the root of a binary tree be null?</h3>
- Only the subtrees are nulled out, the root always remains and will never be set to null.
<h3>What is null root?</h3>
- null-, root. -null- comes from Latin, where it has the meaning "none; not one.
- '' This meaning is found in such words as: annul, null, nullify.
To learn more about it, refer
to brainly.com/question/24448358
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Answer:
The output of the given code as follows:
<u>Output:
</u>
1122
Explanation:
In the given java code the two for loop is defined, which can be described as follows:
- In the first loop, a"loop" variable is used, which starts from 1 and ends when the value of loop is less than 3, inside the loop a print function is used, that print value 1.
- In the next step, another for loop is declared, inside the loop a variable "loop2" variable is used, that's working is the same as the above loop, but in this loop, it will print a value, that is 2.
Answer:
Please check the explanation
Explanation:
That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.
#include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "****WELCOME TO THE GUESS THE NUMBER GAME!****\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); }
Answer:
True
Explanation:
There are four paths in this network. A is an immediate predecessor of C and of D. B is also an immediate predecessor of C and of D. C and D are both immediate predecessors of E. Given the above scenario
