This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).
I have no idea what this is asking honestly but i hope you figure it out
Answer:
Step-by-step explanation:
why dont you like spinach? it tastes bitter to me
why am is so cold? i left my coat in the car
Why was i late for school? i forgot to set my alarm
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.

The probability is 1/57.
Answer: 30
Step-by-step explanation: 30 is the first multiple that both 5 and 6 share, and as such should be the denominator