So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.
so :
180 - 106 = 74 ( sum of the other 2 angles )
74/2 = 37 ( sum of angle HMA / HAM )
angles on a straight line add up to 180.
180-37=143 ( angle x )
since triangle YMH is also an isosceles,
180-37=143
143/2=71.5 ( angle w )
Answer:
BRUH THIS WAS ON MY TEST AND BRUH HONESTLY I HAVE NO CLUEE
Answer:
x=9
Step-by-step explanation:
y=3x+18=5x
thus 3x+18=5x
subtract 3x from both sides 18=2x
simplify for x x=9
Answer:
(1, 5)
Step-by-step explanation:
When the center is the origin, the dilation factor multiplies each coordinate:
(2, 10) ⇒ (1/2)(2, 10) = (1, 5)
