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erastovalidia [21]
3 years ago
7

A number cube is rolled 30 times, and a number less than four comes up 22 times. What is the experimental probability that a num

ber less than four is rolled?
A.) 1/6

B.) 4/15

C.) 11/15

D.) 1/22
Mathematics
2 answers:
Goryan [66]3 years ago
8 0
Your answer to this question is ( c )
serg [7]3 years ago
5 0

experimental probability 22/30

11/15

Answer Choice C

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2x+4(7−x) HELP PLEASE IM DEPERATEEEEE
goldenfox [79]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{ - 2x + 28}}}}}

Step-by-step explanation:

\sf{2x + 4(7 - x)}

Distribute 4 through the parentheses

\dashrightarrow{ \sf{2x + 28 - 4x}}

Collect like terms

\dashrightarrow{ \sf{2x - 4x + 28}}

\dashrightarrow{ \sf{ - 2x + 28}}

Hope I helped!

Best regards! :D

4 0
3 years ago
Read 2 more answers
what is the algebraic equation product of 3 and a squared number is twice the sum of the number and 4
Katyanochek1 [597]
Let n = number

" product of 3 and a squared number" translates to 3n²

"sum of the number and 4" translates to n + 4

The word "is" becomes your equals sign. 

3n² = n + 4 is your equation. 
6 0
3 years ago
Find the solution set for the following problem. 5 diminished by 3 times a number is at most 11.
leva [86]
For this case, the first thing we are going to do is define the following variable:
 x = unknown number
 We now write the following inequality:
 5-3x <= 11
 We clear x:
 5-11 <= 3x
 -6 <= 3x
 -6/3 <= x
 -2 <= x
 The solution set is:
 [-2, inf)
 Answer:
 
the solution set is:
 
[-2, inf)
4 0
3 years ago
Vector u has its initial point at (21,12) and its terminal point at (19,-8). Vector v has a direction opposite that of u, whose
agasfer [191]

Step-by-step explanation:

517÷4685568π√7%+66×74367

7 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
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