Your equation is correct.
Answer:
Please,I don't get your question & kindly be specific
There is a formula which employs the use of determinants and which helps us calculate the area of a triangle if the vertices are given as 
. The formula is as shown below:
Area=
Now, in our case, we have: 
, and
Thus, the area in this case will become:
Area=
Therefore, Area=![\frac{1}{2}\times [[3(-1\times 1-(-5)\times 1]-3[3\times 1-(-2)\times 1]+1[3\times -5-2]]= \frac{1}{2}\times -20=-10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B%5B3%28-1%5Ctimes%201-%28-5%29%5Ctimes%201%5D-3%5B3%5Ctimes%201-%28-2%29%5Ctimes%201%5D%2B1%5B3%5Ctimes%20-5-2%5D%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-20%3D-10)
We know that area cannot be negative, so the area of the given triangle is <u>10 squared units</u>.
Answer:
B. y = 5/2x - 14
Step-by-step explanation:
Find the slope of the original line and use the point-slope formula y
−
y
1
=
m
(x
−
x
1
) to find the line parallel to y
=
5
/2
x
−
10
.
y
=
5
/2
x
−
14 PARALLEL
...................................................................................................................................................
Find the negative reciprocal of the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line perpendicular to y
=
5
/2
x
−
10
.
y
=
−
2
/5
x
−
157
/5 PERPENDICULAR
Answer:
.4
Step-by-step explanation:
Root of 12 is 3.5
Root of 15 is 3.9
3.9 - 3.5 = .4
