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4 years ago

What is u^+6u-27 factoring

Mathematics

1 answer:

MissTica4 years ago

7 0

U² + 6u - 27
u² + 9u - 3u - 27
(u - 3)(u + 9)

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Jaida simplified and evaluated this expression 2x+5x-4+1 when x=3. What answer should jaida get

jenyasd209 [6]

The answer to this problem is 18

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3 years ago

There's a pair of points (3,5), (x,15) and a slope of 2 how do I find x

sergeinik [125]

You have the slope and you have two points, so you can use the slope equation to find x.

$b=\frac{(y_2-y_1)}{(x_2-x_1)} \\2=\frac{(15-5)}{(x-3)} \\2(x-3)=(15-5)\\2x-6=10\\2x=16\\x=8$

So your answer is x = 8.

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3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

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3 years ago

How do u find the domain of radical functions.

weqwewe [10]

First determine the index of the radical

If the index is an even number, set the expression inside the radical greater than or equal to zero.

Solve the equation found above :)

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4 years ago

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JulijaS [17]

Answer:

..fyjnvcftuukloyrsszxccccccx

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3 years ago