Hi there!
We are given the function -
and are told to find the limit of the function.
The limit would be n approaches infinity, giving us an answer of
-1.
Here is how you solve this:
Divide by (n + 1)! -
Now, we can refine the function -
Now, just simplify. This gives us -
We can use the rule
to simplify the whole thing to get 1. Finally, we plug it back into our second derived equation to get 1/-1, which simplifies to -1. Therefore, the answer is
-1. Hope this helped and have a great day!
Answer:
a^2-12a+35
Step-by-step explanation:
(a-7)(a-5)
a^2-7a-5a+35
a^2-12a+35
First, create a rule for this sequence.
Let a(1) be the first term (which here happens to be 1).
The next term, a(2), is twice the previous term, that is, twice 1, or 2.
a(3) = 2a(2) = 2(2) = 4
This is called a "recursive function."
The 3rd term is 4. The next, which is a(3) is 2*4, or 8.
Note that there's an alternative approach. The first term, a(1), is 1; the next is a(2) = a(1)*2^(2-1) = 1*2^1=2
the next is a(3) = 1*2^(3-1) = 1*2^2 = 4
So the rule is a(n) = a(1)*2^(n-1).
So a(8) is a(1)*2^(8-1) = 1*2^7 = 2^3*2^4 = 8(16) = 128
I believe the answer is B >15