HURRY this needs to be done fast!!!

PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

Samantha puts an initial $500 into a savings account. The account has a 4% annual compound interest rate. What is the function t

Licemer1 [7]

I use a bit of a different looking formula.

A(t)=P(1+r/n)^nt

P=amount of money. (500)
r= rate (in decimal. 4%=0.04)
n=number of times per year (1 in this problem)
t=amount of time. (5 years)

Plugged in it looks like this:

A(t)=500 (1+ 0.04/1)^1x5

Then I put it into my calculator like this:

0.04/1+ 0.04

Then add one to the above answer:

0.04+1=1.04

Then raise the above answer to the 1x5:

1.04^5=1.2166......

Then multiply the above answer by 500:

1.2166.... x 500=608.3264512

She has $608 after 5 years.

Hope this helps, let me know if you have any questions.

5 0

2 years ago

Just go down the row and say yes no yes no in order!you don't have to type the whole thing out

tangare [24]

Answer:

1) yes

2) no

3) yes

4)no

5)no

Step-by-step explanation:

8 0

2 years ago

A quantity with an initial value of 8600 grows exponentially at a rate of 20% every 2 minutes. What is the value of the quantity

Hatshy [7]

Answer:

23400 x 8/100 = 1872 = the loss

1872 : 12 = 156= the loss each month

156/1872*100% = 8.33 % then round it

3 0

3 years ago

Write the polynomial function with the given zeros. 5. x= -1,-1, 6

Allushta [10]

Answer:

Step-by-step explanation:

There are many such polynomials, but the one with leading coefficient of 1 is

y = (x+1)(x-1)(x-6) = x^3 - 6x^2 - x + 6

Not sure what you want to do with the 5, If that is the y-intercept, then since

(1)(-1)(-6) = 6, we will need

y = 5/6 (x^3 - 6x^2 - x + 6)

5 0

3 years ago