1) Which two teams had the greatest point difference?
Delta and Beta (85 - 25 = 60)
2) Which two teams had the least point difference?
Delta and Gamma (85 - 75 = 10)
3) What was the average score of the 5 teams?
(45+25+75+85+65) / 5 = 295 / 5 = 59
4) How many more points did Epsilon score than Beta?
Epsilon: 65
Beta: 25
65 - 25 = 40
Epsilon scored 40 more than Beta
<span>5) Which teams scored more than 2 times Beta’s score?</span>
twice of Beta = 25 x 2 = 50
answer
Gamma (75) , Delta (85) and Epsilon (65)
Answer:
81
Step-by-step explanation:
let the terms be a,ar,ar²
r=2/3
a+a(2/3)+a(2/3)²=171
multiply by 9
9a+6a+4a=171×9
19 a=171×9
a=(171×9)/(19)
a=9×9=81
Answer:
Please check the explanation.
Step-by-step explanation:
Part a)
Given that the two parallel lines are crossed by a transversal line.
Given that
m∠2 = 2x + 54 and m∠6 = 6x - 11
Angle ∠2 and ∠6 are corresponding angles.
Corresponding angles are congruent.
Thus,
m∠2 = m∠6
2x + 54 = 6x - 11
flipe the equation
6x - 11 = 2x + 54
subtract 2x from both sides
6x - 2x - 11 = 2x - 2x + 54
4x - 11 = 54
adding 11 to both sides
4x - 11 + 11 = 54 + 11
4x = 65
dvide both sides by 4
4x/4 = 65/4
x = 16.2500 (round to 4 decimal places)
Part b)
We have already determined
x = 16.2500
Given
m∠2 = 2x + 54
substitute x = 16.2500 in the euation
= 2(16.2500) + 54
= 86.5°
As angle ∠2 and angle ∠1 lie on a straight line. Hence, the sum of their angles must be 180°.
i.e.
m∠1 + m∠2 = 180°
substituting m∠2 = 86.5° in the equation
m∠1 + 86.5° = 180°
subtracting 86.5° from both sides
m∠1 + 86.5° - 86.5° = 180° - 86.5°
m∠1 = 93.5°
Therefore, the measure of angle m∠1 is:
Given:
The slope of the line is m=0.
The line passes through the point P(-9,-3).
To find:
The equation of the line in standard form.
Solution:
Standard form of a line is:
The slope intercept form of the line is
Where, m is the slope and 
is the point on the line.
It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is
Therefore, the standard form of the given line is .
Let's first write the equation given
x²+6x-13=0
They have told us to use "Completing the square" method.
So we need write x²+6x-13 as a whole square.
x²+6x-13=0
x²+(2*3*x)-9-4 = 0
x²+(2*3*x)-3²=4
Now we can write the LHS as:
(x - 3)²=2²
Hence,
x-3 can either be 2 or -2
Now,
x - 3=2
x=5
Or,
x - 3=-2
x=1
Therefore now we know that x can either be 1 or 5. So the correct answer is Option B.
