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Tatiana [17]
2 years ago
8

Compra mercancía por 2580000 más el IVA del 19%y retefuente del 3,5% u se cancela en efecyivo

Mathematics
2 answers:
Ainat [17]2 years ago
3 0

Answer:

i dont speak or type spanish

Step-by-step explanation:

irina1246 [14]2 years ago
3 0

Answer: Sorry, i don't speak spanish dude

Step-by-step explanation: Would you like to translate it for me?

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He will have $840 in 24 months, which is two years.
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What is a solution to the equation x 2 = 121.
gizmo_the_mogwai [7]

x=11,-11 there you  go


6 0
3 years ago
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Find the length of the chord made by 3x2 - y2 = 3 and y + x – 5 = 0.
MArishka [77]

Answer:

The correct answer is "9√2 units".

Step-by-step explanation:

The given equations are:

⇒ 3x^2-y^2=3...(equation 1)

⇒ y+x-5=0...(equation 2)

According to the 2nd equation, we get

⇒ y+x-5=0

⇒              y=5-x

On substituting the value of "y" in the 1st equation, we get

⇒  3x^2-y^2=3

     3x^2-(5-x)^2=3

     3x^2-(25+x^2-10x)=3

     2x^2+10x-28=0

On taking common, we get

     x^2+5x-14=0

On applying factorization, we get

     x^2+7x-2x-14=0

   x(x+7)-2(x+7)=0

           (x+7)(x-2)=0

                        x+7=0

                              x=-7

or,

                         x-2=0

                                x=2

Now,

The points are:

(-7, 12) = (x₁, y₁)

(2, 3) = (x₂, y₂)

By using the distance formula, the length of chord will be:

= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the values in the above formula, we get

= \sqrt{(2-(-7))^2+(3-12)^2}

= \sqrt{(9)^2+(-9)^2}

= \sqrt{81+81}

= 9 \sqrt{2} units

8 0
2 years ago
Help me please!! on the puzzle please
grin007 [14]
U actually did it right to let u know and u r so welcome
8 0
3 years ago
What is the greatest fraction you can make using the digits 4, 7, and 9?
wel

Answer:

  (7^9)/4 = 40,353,607/4

Step-by-step explanation:

Assuming each digit is used once and exponentiation is allowed, the largest numerator and smallest denominator will result in the largest fraction.

__

If other functions, such as factorial are allowed, then there might need to be a limit on the number of times they are applied. For example,

  (7!)^(9!)/4 has about 1 million digits

something like ...

  ((7!)^(9!))!/4 has many more digits than that

and you can keep piling on the factorial symbols to any desired depth.

6 0
3 years ago
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