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3 years ago

What is the solution to the equation 3x + 2(x − 9) = 8x + x − 14? (1 point)

Mathematics

1 answer:

solong [7]3 years ago

6 0

Answer:

B. -1

Step-by-step explanation:

STEP 1: Simplify 3x+2(x−9).

$5x-18=8x+x-14$

STEP 2: Add 8x and x.

$5x-18=9x=-14$

STEP 3: Move all terms containing x to the left side of the equation.

$-4x-18=-14$

STEP 3: Move all terms not containing x to the right side of the equation.

$-4x=4$

STEP 4: Divide each term by −4 and simplify.

$x=-1$

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Identify the terms, coefficients, and constants in the expression $18x+7$ .

BartSMP [9]

Coefficients: 18
Constants: 7
Variable (if u need help on this): X

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3 years ago

Solve the equation x+9=11<br> X=

Harman [31]

Answer:

Step-by-step explanation:

11-9=2

X=2

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4 years ago

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A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

$\chi^2_{\alpha/2}=36.191$

$\chi^2_{1- \alpha/2}=7.633$

And replacing into the formula for the interval we got:

$\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}$

$8.400 \leq \sigma^2 \leq 39.827$

So the 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

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3 years ago

What is the answer for ½+¼⅝

Sphinxa [80]

Answer:

1 3/8

$SOLUTION$

$add \: \frac{1}{2} + \frac{1}{4} + \frac{5}{8}$

$= \frac{4 + 2 + 5}{8}$

$= \frac{11}{8}$

=1 3/8

I hope it helps

have a great day

$#Liliflim$

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3 years ago

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9. What is the relationship between the estimates you found for the lengths of the two equators?4 grade student

Ann [662]

7. You have the equator's length of four planets, the distances are given in kilometers

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1 year ago