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blagie [28]
3 years ago
12

Find the difference (5-8i)-(-6-11i)

Mathematics
2 answers:
vredina [299]3 years ago
6 0
I think this is the 11+3i
Andreyy893 years ago
5 0
<h3>Answer:   11+3i</h3>

Work Shown:

(5-8i)-(-6-11i)

5-8i+6+11i ....... distribute

(5+6) + (-8i+11i) .... group like terms

11 + 3i ..... combine like terms

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Irrational equations 64^1/3 how to simplify?
balandron [24]
For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.

So, 64^(1/3) is the third root of 64, which is equal to 4.
6 0
4 years ago
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Simplify 2(5*)<br><br> What is the answer
Cloud [144]

Answer:

the answer is 10 multiply maybe

3 0
3 years ago
Is this relationship proportional why or why not?
taurus [48]

Answer:

no

Step-by-step explanation:

to be proportional, every step of 1 in the upper row, must equal an equal step in the lower row.

from 1 to 2: +15

from 2 to 3: +18

not the same so not proportional

3 0
3 years ago
Please HELP PAST DUE I NEED THE GRADE help!!!
ArbitrLikvidat [17]

Answer:

(A:) I created a scatter plot similar to the one i used for mine, this is for the first part of your question

(B:) Positive Association

Step-by-step explanation:

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7 0
4 years ago
Two factories — Factory A and Factory B — design batteries to be used in mobile phones. Factory A produces 60% of all batteries,
elena-s [515]

Answer:

Probability that a battery is both made by Factory A and defective is 0.012 or 1.2%.

Step-by-step explanation:

We are given that Two factories — Factory A and Factory B — design batteries to be used in mobile phones. Factory A produces 60% of all batteries, and Factory B produces the other 40%.

2% of Factory A's batteries have defects, and 4% of Factory B's batteries have defects.

Let the Probability that factory A produces batteries = P(A) = 0.60

Probability that factory B produces batteries = P(B) = 0.40

<em>Also, let D = event that battery is defective</em>

Probability that batteries have defects given that it is produced by Factory A = P(D/A) = 0.02

Probability that batteries have defects given that it is produced by Factory B = P(D/B) = 0.04

Now, <u>probability that a battery is both made by Factory A and defective</u> = Probability that factory A produces batteries \times Probability that batteries have defects given that it is produced by Factory A

                       =  P(A) \times P(D/A)

                       =  0.60 \times 0.02 = 0.012  or  1.2%

Therefore, the probability that a battery is both made by Factory A and defective is 1.2%.

4 0
3 years ago
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