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sertanlavr [38]
3 years ago
6

50 points!!! Can someone show the work for this for me to look at.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0
I think the answer is 3 but I'm not sure

36+2 / 6 = 1/2 so A = 3
Serga [27]3 years ago
7 0
I think the answer is 3.
OK!!!
Ur welcome.
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krek1111 [17]

Answer:

answer in the attached image

Step-by-step explanation:

hope this helps, have a nice day :)

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3 years ago
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Please help, multiple choice need halp--
Verdich [7]

Answer:

Where is the function shown below?

Step-by-step explanation:

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3 years ago
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A researcher is planning to compare the effects of two different types of lights on the growth of bean plants. She expects that
kicyunya [14]

Answer:

The sample size is  n  = 36

Step-by-step explanation:

From the question we are told that

   The sample standard deviation is  s =  1.5

  The mean difference of the two groups is  \=x _ 1 - \=x_2 =  1

   The standard error is  SE =  \frac{ \= x_1 - \= x_2}{4}

=>                                      SE =  \frac{1}{4}

Let assume that the confidence level is 95% hence the level of significance is  

   \alpha = (100-95)\%

=> \alpha = 0.05

So the critical value of  \frac{\alpha }{2} obtained from the normal distribution table is

     Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

     E =  Z_{\frac{\alpha }{2} } * SE    

   E =  1.96 * \frac{1}{4}

    E = 0.49

Generally the sample size is mathematically represented as

  n =[ \frac{Z_{\frac{\alpha }{2}  * s^2}}{E}]^2

=> n  = [\frac{1.96 * 1.5}{0.49} ]^2

=> n  = 36

6 0
3 years ago
How do u convert 12 years to hours
maw [93]

Answer:

the answer is 105120

Step-by-step explanation:

24 hours in a day, 365 days in a year. 365 multiplied by 24 equals 8760 multiply that by 12 equals 105120

5 0
3 years ago
How do you find the first five terms of a sequence defined recursively
Blizzard [7]
Interesting question. Good to know for computer science.
Suppose you have a function like 
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1

a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3

an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3 
a3 = 7

a4 = a3 + 3
a4 = 7 + 3
a4 = 10

a5 = a4+ 3
a5 = 10 + 3
a5 = 13

I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16

a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.

So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
6 0
3 years ago
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