There are 99 palindromic numbers between 10 and 1000: 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, 212, 222, 232, 242, 252, 262, 272, 282, 292, 303, 313, 323, 333, 343, 353, 363, 373, 383, 393, 404, 414, 424, 434, 444, 454, 464, 474, 484, 494, 505, 515, 525, 535, 545, 555, 565, 575, 585, 595, 606, 616, 626, 636, 646, 656, 666, 676, 686, 696, 707, 717, 727, 737, 747, 757, 767, 777, 787, 797, 808, 818, 828, 838, 848, 858, 868, 878, 888, 898, 909, 919, 929, 939, 949, 959, 969, 979, 989, 999.
No. there are no integers between 0 and 1 because integers are the numbers which don't have any fractions and decimals. between 0 and 1 only decimals and fractions are present
The value of (f + g)(x) is x² + x - 14
Given: f(x) = 5x - 6
g(x) = x² - 4x - 8.
To find the value of (f + g)(x)
What are functions?
Functions are expressions or a rule that defines the relation between different variables which are described for a given problem.
Let's solve the question:
f(x) = 5x - 6
g(x) = x² - 4x - 8
We know from the algebra of functions that:
(f + g)(x) = f(x) + g(x)
f(x) + g(x) = (5x - 6) + (x² - 4x - 8)
Now grouping like terms:
= x² + (5x - 4x) + (-6 - 8)
= x² + x - 14
Therefore, (f + g)(x) is x² + x - 14
Hence the value of (f + g)(x) is x² + x - 14
Know more about "functions" here: brainly.com/question/12431044
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