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s2008m [1.1K]
3 years ago
11

Which of the following equations has an infinite number of solutions?

Mathematics
1 answer:
RSB [31]3 years ago
6 0
The answer is C

Simplify both sides of the equation and combine like terms.
You’re left with 7x+5 = 7x+5
Subtract 7x on both sides
Leaves you with
5=5
Subtract 5 on both sides
0=0
Infinite number of solutions.
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Help asap info in side the file/ picture
timofeeve [1]

Answer:

600 times 60 equals 36000

1,000 times 60 equals 60000

6000 times 30 equals 18000

Step-by-step explanation:

3 0
3 years ago
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At a sale, coats were sold for $17 each. If the coats originally cost $20 each, what percentage of its original price was a coat
PtichkaEL [24]
15% off
$20 is 100%
$10 is 50%
$1 is 5%

Use that to work them out and voila
8 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
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Can y’all help me with this
Aleonysh [2.5K]

Answer:

it's the last one *25,000 J

Step-by-step explanation:

3 0
3 years ago
I know the answer is 324 but can someone tell me step by step how to solve it?​
love history [14]
Do what is in brackets first, then the multiplication.
5 0
3 years ago
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