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s2008m [1.1K]
2 years ago
11

Which of the following equations has an infinite number of solutions?

Mathematics
1 answer:
RSB [31]2 years ago
6 0
The answer is C

Simplify both sides of the equation and combine like terms.
You’re left with 7x+5 = 7x+5
Subtract 7x on both sides
Leaves you with
5=5
Subtract 5 on both sides
0=0
Infinite number of solutions.
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Select all the equations where m = 4 is a solution.
Aneli [31]
The answers are A,B, and E. Hope this helps. :)
4 0
2 years ago
Simplify x to the 1/3 power (x to the 1/2 power + 2x to the 2 power )
OverLord2011 [107]

Answer:

x^(5/6) + 4(x^(7/3))


Step-by-step explanation:

Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )


Simplify x^(1/3) × (x^(1/2) + (2x)^2)

= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)

= x^(1/3+1/2) + 4(x^(1/3+2))

= x^(5/6) + 4(x^(7/3))


x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x


x^(1/2) = √2 = y such that y^2 = x

(2x)^2 = 4x^2






6 0
3 years ago
Gabe rolled 14 strikes out of 70 attempts. What percent of Gabe's attempts were strikes?
Airida [17]

Answer:

20%

Step-by-step explanation:

14/70x100=20%

5 0
3 years ago
Based on historical data, your manager believes that 40% of the company's orders come from first-time customers. A random sample
Vedmedyk [2.9K]

Answer:

P(0.26 \leq p \leq 0.43)=0.7204-0.0032=0.7172

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The population proportion have the following distribution

p \sim N(p=0.4,\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.4(1-0.4)}{91}}=0.0514)

And we can solve the problem using the z score on this case given by:

z=\frac{p_o -p}{\sqrt{\frac{p(1-p)}{n}}}

We are interested on this probability:

P(0.26 \leq p \leq 0.43)

And we can use the z score formula, and we got this:

P(\frac{0.26 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}} \leq Z \leq \frac{0.43 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}})

P(-2.726 \leq Z \leq 0.584)

And we can find this probability like this:

P(-2.726 \leq Z \leq 0.584)=P(Z

7 0
3 years ago
Find the product in its simplest form<br><br> 2/5 * 3/7
Mamont248 [21]

Answer:

6/35

Step-by-step explanation:

I just used my calculator...

6 0
2 years ago
Read 2 more answers
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