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Vika [28.1K]
3 years ago
8

A parallelogram has vertex at (-5 , -1) (-2, -1), (-3,-4), and (-6,-4). What is the approximate perimeter of the parallelogram r

ound your answer to the nearest hundredth
Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

12.4 units

Step-by-step explanation:

We have to find the length of the sides of the parallelogram which is calculated using the formula for Distance

= √(x2 - x1)² + (y2 - y1)² where we are given the vertices (x1, y1) and (x2, y2)

For side A

(-5 , -1) (-2, -1)

= √(-2 -(-5))² + (-1 - (-1))²

= √(-2 + 5)² + (-1 + 1)²

= √3² + 0

= √9

= 3 units

For side B

(-2, -1), (-3,-4)

= √(-3 -(-2))² + (-4 -(-1))²

= √(-3 + 2)²+ (-4 + 1)²

= √-1² + -3²

= √1 + 9

= √10 units

= 3.1622776602 units

Approximately = 3.2 units

For side C

(-3,-4), (-6,-4).

= √(-6 -(-3))² + (-4 - (-4))²

= √(-6 + 3)² + (-4 + 4)²

= √-3² + 0²

= √9

= 3 units

For side D

(-5 , -1), (-6,-4)

= √(-6 - (-5))² + (-4 - (-1))²

= √(-6 + 5)² + (-4 + 1)²

= √-1² + -3²

= √1 + 9

= √10 units

= 3.1622776602 units

Approximately = 3.2 units

From the above calculation , we can see that,

side A = side C

side B = side D

The formula for the Perimeter of a Parallelogram is = 2(Side a + Side b)

= 2(3 + 3.2) units

= 2(6.2) units

= 12.4 units

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