Let G be the granola we need (in pound)
Let N be the nut we need (in pound)
Trail mix cost $5.00 per pound---> cost for 7 pound = 5 x 7 = $ 35
4.5G+7N= 35
G+ N = 7
Therefore G = 5.6 N=1.4, we would need 5.6 pound granola & 1.4 pound nut
Answer:
No, the answer is 120 plants per square foot
Step-by-step explanation:
What I did was first figure up the area of the triangle. You want to do this because the area will tell you how many square feet are in the garden. In order to find this, you need to use this formula: 1/2 b·h
Plug in the numbers like this: 1/2·15·8
15 is the base of the triangle, while 8 is the height of the triangle. Now solve your equation.
15·8=120
1/2·120=60
Area = 60
Now you know that the area is 60ft². So there are 60 square feet in the whole garden. But, we're not done yet. Jessica wants to put 2 plants in every 1 square foot. So now, we need to multiply 60 by 2 in order to get 2 plants in every 1 square foot.
60·2=120
Jessica can put 120 plants in the garden if she is wanting 2 plants per square foot.
I hope this makes sense and is easy to understand. Please let me know if you need any more help or clarification. I'm always happy to help! Have a great day and good luck!!
For #32,
P=2L+2W
Subtract 2W from both sides, and swap left and right
2L = P-2W
Divide by 2
2L/2=(P-2W)/2
L = P/2 - 2W/2
L=P/2 - W
For #35
Most of the expenses are in fractions (of the original amount, A), so they can be added:
A/4 + A/5 + 2A/5 + 750 = A
add the fractions, with a common denominator of 20,
5A/20 + 4A/20 + 8A/20 +750 = A
(5A+4A+8A)/20 +750 = A
17A/20 + 750 = A
Now subtract 17A/20 from both sides and swap left and right
A - 17A/20 = 750
(3/20)A = 750
Multiply both sides by 20/3 (to make one unit of A on the left)
(3/20)*(20/3) A = 750*20/3
A =250*20=5000
Answer:
The margin of error for a 99% confidence interval for the population mean is 1.8025.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
In this problem:
So
The margin of error for a 99% confidence interval for the population mean is 1.8025.
