I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².
Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.
Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.
Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.
Add each length up and you get a perimeter of roughly 11.4
The answer is Day 3. The blue bar for day 3 is the tallest, which means that was the highest amount.
Answer:
24cm
Step-by-step explanation:
6x4=24
Answer:
c=8
Step-by-step explanation:
Where do I start when I'm trying to solve a word problem? ... 44=A+B+C=(32C)+3C+C=112C. Multiplying both ends by 211 we find. C=8 ... Mac's collection contain 8 more than twice as many as Ted's.
Let Gavin be G
Let Seiji be S
G + S = 425
G = 25 + S
I can't really graph, but plug in some numbers to G and S that works in BOTH equations. Then graph it.
G + S = 425
G = 25 + S
(25 + S) + S = 425
2S + 25 = 425
2S + 25 (-25) = 425 (-25)
2S = 400
2S/2 = 400/2
S = 200
Seiji made 200 dollars
Now choose one of the equations to use (the easier the better) in this case i will choose this one:
G = 25 + S
pug in 200 into S (because that is how much Seiji made)
G = 25 + (200)
G = 225
Seiji made 200, Gavin made 225
200 + 225 = 425, which is the total amount the made
hope this helps
