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algol13
3 years ago
12

Find the constant of variation for the quadratic variation.

Mathematics
1 answer:
yarga [219]3 years ago
6 0
The answer is 6.  It is the second option.
y = kx^2 
Use any coordinate in the set.
The missing is k, to find it, use the equation
<span>24 = k(2^)
= 4k </span>
<span>k = 6 </span>
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Anuta_ua [19.1K]

Answer:yes

Step-by-step explanation:

There is one very important exception to the rule that multiplying or dividing an inequality is the same as multiplying or dividing an equation. Whenever you multiply or divide an inequality by a negative number, you must flip the inequality sign.

6 0
3 years ago
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NEED HELP ASAP
Stels [109]
<span>9,    12,    19,    30,    ...

</span>formula for the nth term is;

<span>2n^2 + 3n - 10</span>
6 0
2 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
1 year ago
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