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algol13
4 years ago
12

Find the constant of variation for the quadratic variation.

Mathematics
1 answer:
yarga [219]4 years ago
6 0
The answer is 6.  It is the second option.
y = kx^2 
Use any coordinate in the set.
The missing is k, to find it, use the equation
<span>24 = k(2^)
= 4k </span>
<span>k = 6 </span>
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ms. Mitchell wants to buy a new pair of boots that originally cost $65.00 but are now on sale for 15% off. What is the sale pric
Goryan [66]

$55.25c ☺️ Because 10% of 65 is $6.50 and 5% of $3.25 and 6.50 + 3.25 = 9.75 and 65 - 9.75 = 55.25 ☺️ Hope I helped ☺️

5 0
3 years ago
Read 2 more answers
Find ten solutions to the linear equation to the linear equation 1/2x+y=5
yuradex [85]

Answer:

(0,5), (2,4), (4,3), (6,2), (8,1), (10,0), (12,-1), (14,-2), (16,-3), (18,-4), and (20,-5)

Step-by-step explanation:

The given linear equation is :

\frac{1}{2} x + y = 5

Or

y =  -  \frac{1}{2} x + 5

Any ordered pair that satisfies this equation is a solution.

When x=0,

y =  -  \frac{1}{2}  \times 0 + 5 = 5

(0,5) is a solution

When x=2,

y =  -  \frac{1}{2}  \times 2+ 5 = 4

(2,4) is a solution.

When x=4,

y =  -  \frac{1}{2}  \times 4+ 5 = 3

(4,3) is a solution;

When x=6:

y =  -  \frac{1}{2} \times 6+ 5 = 2

(6,2).

When x=8,

y =  -  \frac{1}{2}  \times 8 + 5 = 1

Another solution is (8,1)

When x=10,

y =  -  \frac{1}{2}  \times 10 + 5 = 0

(5,0) is a solution

When x=12,

y =  -  \frac{1}{2}  \times 12+ 5 =  - 1

(12,-1) is a solution.

When x=14,

y =  -  \frac{1}{2}  \times 14+ 5 =  - 2

When x=16, we get:

y =  -  \frac{1}{2}  \times 16 + 5 =  - 3

When x=18, we get:

y =  -  \frac{1}{2}  \times 18+ 5 =  - 4

7 0
3 years ago
What is the inverse of the function f(x) = x – 12?
SashulF [63]
y=x-12\\&#10;x=y+12\\&#10;f^{-1}(x)=x+12
7 0
3 years ago
The coordinates of the points represent the vertices of a rectangle. P(2,2) Q(6,2) R(6,5) S (2,5) What is the perimeter of the r
BlackZzzverrR [31]

Answer:

14

Add the lengths of all sides together, I would recommend graphing to see for future reference!

8 0
3 years ago
Are they inverses or not inverses of eachother?
Maurinko [17]

Answer:

They are not inverse

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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