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3 years ago

Someone help me out with this and please get it all correct.

Mathematics

1 answer:

Law Incorporation [45]3 years ago

6 0

Answer:

Step-by-step explanation:

9(2+1)=18+9

9(5-2)=45-18

4(1-8)=4-32

9(2=9)=18+81

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What is a tenth of a decimal ?

trapecia [35]

One decimal place to the left decimal point is the place.

8 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

Given that x and y are positive integers, solve the equation x² - 4y² = 13

zvonat [6]

<h3>Answer: x = 7 and y = 3</h3>

=====================================================

Explanation:

Apply the difference of squares rule

x² - 4y² = 13

x² - (2y)² = 13

(x - 2y)(x + 2y) = 13

Since x and y are positive integers, this means x-2y and x+2y are both integers as well.

The value 13 is prime. Its only factors are 1 and 13

Since the above equation shows 13 factoring into x-2y and x+2y, then we have two cases:

A) x-2y = 1 and x+2y = 13
B) x-2y = 13 and x+2y = 1

----------------

Let's consider case A

We have this system of equations

$\begin{cases}x-2y = 1\\x+2y = 13\end{cases}$

Add the equations straight down

x+x becomes 2x
-2y+2y becomes 0y = 0 which goes away
1+13 becomes 14

Therefore we have 2x = 14 solve to x = 7

From here, plug this into either equation to solve for y

x-2y = 1

7 - 2y = 1

-2y = 1-7

-2y = -6

y = -6/(-2)

y = 3

You should get the same result if you used x+2y = 13

----------------

Since we've found that x = 7 and y = 3, notice how case B is not possible

Example: x-2y = 13 becomes 7-2(3) = 13 which is false.

Also, x+2y = 1 would turn into 7+2(3) = 1 which is also false.

-----------------

Let's check those x and y values in the original equation

x² - 4y² = 13

7² - 4*(3)² = 13

49 - 4(9) = 13

49 - 36 = 13

13 = 13

The answer is confirmed.

4 0

2 years ago

A jar contains chocolate candies. There are 12 red, 17 blue, 5 green and 6 orange. What is the probability of picking either a g

nataly862011 [7]

Answer:

Step-by-step explanation:

If you sum everything, you'll get 50 candies. Now you know that 50 candies is 100%.

Now you'll calculate the probability:

12 on 50 : 24.00 %

17 on 50 : 34.00 %

5 on 50 : 10.00 %

6 on 50 : 12.00 %

Hope I was helpful :)

Edit :

12/50 17/50 6/50 5/50

7 0

3 years ago

What is the range of<br> f(x) = 3x2^x

ZanzabumX [31]

Range = 0
{y|y > 0}
Hope it helps you

3 0

2 years ago