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11Alexandr11 [23.1K]
2 years ago
13

Find Each Quotient.1.6÷13.8

Mathematics
2 answers:
Step2247 [10]2 years ago
6 0

Answer:

8/69

Step-by-step explanation:

1.6÷13.8

convert the decimal into fraction so 8/5 ÷ 13.8 and 8/5÷69/5 multiply by the reciprocal and reduce the number and you will get 8×1/69

schepotkina [342]2 years ago
3 0
Answers is 8/69 or 0.115942028985507246768
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Help !!!!!!!!!!!!!!!!!!!!!
vladimir1956 [14]

Answer:

12 is the answer thanks for asking in

3 0
2 years ago
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W
Dafna1 [17]

Answer:

  • A. segment A double prime B double prime = segment AB over 2

Step-by-step explanation:

<u>Triangle ABC with coordinates of:</u>

  • A = (-3, 3), B = (1, -3), C = (-3, -3)

<u>Translation (x + 2, y + 0), coordinates will be:</u>

  • A' = (-1, 3), B = ( 3, -3), C = (-1, -3)

<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>

  • A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)

<u>Let's find the length of AB and A''B'' using distance formula</u>

  • d = √(x2-x1)² + (y2 - y1)²
  • AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
  • A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13

<u>We see that </u>

  • AB = 2A''B''

<u>Now the answer options:</u>

A. segment A double prime B double prime = segment AB over 2

  • Correct

B. segment AB = segment A double prime B double prime over 2

  • Incorrect. Should be AB = A''B''*2

C. segment AB over segment A double prime B double prime = one half

  • Incorrect. Should be AB/A''B'' = 2

D. segment A double prime B double prime over segment AB = 2

  • Incorrect. Should be A''B''/AB = 1/2
7 0
3 years ago
Read 2 more answers
Michelle drew a scale drawing of a swimming pool she used the scale 14 millimeters 5 meters in the drawing the pool is 42 millim
Lera25 [3.4K]

EXPLANATION

Let's see the facts:

The scale is---> 14 milimeters ----> 5 meters

Width = 42 milimeters

Applying the unitary method, the actual width of the pool is:

Actual_{}width=42\text{ mm}\cdot\frac{5m}{14\text{ mm}}=15m

The width of the pool is 15m

6 0
10 months ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
PLZ ANSWER APSP IM IN THE TEST RN!!!
olchik [2.2K]

Answer:

x = 38

y = 25

Step-by-step explanation:

To find x, you do

(2x + 5) = (3x - 33)

Subtract 2x from both sides to isolate x on one side, you get:

5 = (x - 33)

Add 33 to both sides to separate the normal number from the x, you get:

38 = x

From there, you plug x into one of the equations

2(38) + 5

The answer's 81, meaning that angle is 81 degrees. Using supplementary angles, you can find that angle ACD = 99, which you can use to find angle BCE. You'll get this equation:

(4y - 1) = 99

Add one to both sides to get rid of it, you get:

4y = 100

Divide by four, to get the y all alone:

y = 25

I hope this helped!

8 0
3 years ago
Read 2 more answers
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