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Irina18 [472]
3 years ago
15

Find the value of each variable.

Mathematics
1 answer:
gavmur [86]3 years ago
7 0
Hey you can use marhway or desmos it has helped me with theses also don’t open any links it can be a scam
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Randomly split the messages into a training set D1 (80% of messages) and a testing set D2 (20% of messages). Calculate the testi
Blizzard [7]

Answer:

In the step-by-step

Step-by-step explanation:

This is the code i created using the R software and the packages "caret" and "e0171".

The script was supposed to work in all general cases.

library(caret)

library(e1071)

# Categorical vector

spam <- c("spam","not_spam")

spam_vec <- sample(spam,60, replace = T)

# Supposing two independent variables so that the kappa will be close to 0.

x1 <- rnorm(60)

x2 <- rnorm(60)

# Creating the dataset

data1 <- cbind(spam_vec,x1,x2)

data1 <- as.data.frame(data1)

names(data1) <- make.names(c("spamvec","x","y"))

# Creating the partition

index <- createDataPartition(data1$spamvec,

                            p=0.8, list=FALSE)

training_data <- data1[index,]

testing_data <- data1[-index,]

fitControl <- trainControl(method = "cv",

                         number = 5,

                         savePred = TRUE,

                         classProb = TRUE)

tune.grid <- expand.grid(C = seq(0, 10, .1))

# Scaling the predictors

preProcess_cs <- preProcess(training_data[, -1],

                                 method = c("center", "scale"))

spam_training_cs      <- predict(preProcess_cs, training_data)

spam_testing_cs       <- predict(preProcess_cs, testing_data)

# Training a Naive Bayes to predict binary outcome

Naive_Bayes_Model=naiveBayes(spamvec ~.,

                            data=spam_training_cs,

                            tuneGrid = tune.grid,

                            trControl = fitControl)

# Confusion matrix

prediction <- predict(Naive_Bayes_Model, spam_testing_cs)

confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

confM <- confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

accuracy <- confM$overall[1]

accuracy

3 0
3 years ago
PLEASE HELP I'LL GIVE BRAINLIEST
ivanzaharov [21]

Okay, so I multiplied the feet in height of the shape, and I ended up getting 7,125. I hope this helps you out!

8 0
3 years ago
Details
ale4655 [162]

Answer:

94 children, 64 students, and 47 adults attended the movie theater.

Step-by-step explanation:

Let; a be for adults, s for students, and c for children.

Make a system to solve for the amount of people.

c/a = 2

a + 2a + s = 205

3a + s = 205

Simplify.

s = 205 - 3a

s = 205 - 3a

c = 2a

Plug it in.

5c + 7s + 12a = 1482

10a + 7(205 -3a) + 12a = 1482

10a + 1435 - 21a + 12a = 1482

a + 1435 = 1482

a = 47

Substitute.

c = 2(47)

c = 94

Solve.

s = 205 - 3(47)

s = 64

5 0
3 years ago
Which is irrational? <br> 32/3<br> 1.7284927172646362.....<br> 1.3232323232....<br> 1.5
emmasim [6.3K]

Answer:

Step-by-step explanation:

32/3

=10.666666667

4 0
4 years ago
Evaluate <br><br> 0<br> ∫ ( 3^3 - 5^2) dx <br> -2
Jobisdone [24]
3^3 = 27
5^2 = 25
27 - 25 = 2

integral of 2 = 2x

(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4

If you did not make any mistakes in typing your question
the answer would be 4
4 0
3 years ago
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