T=number of years since start of the study.
y=city´s population.
first year:
y=390,000+0.073(390,000)=390,000(1+0.073) (=418470)
Second year:
y=(390,000(1+0.073) + 0.073(390,000(1+0.073) =
=390,000(1+0.073) (1+0.073)
=390,000(1+0.073)²
(≈449,018.31)
Third year: if you calculate it you would have:
y=390,000(1+0.073)³
Fourth year: if you compute it you would have:
y=390,000 (1+0.073)⁴
t th year:
y=390,000(1+0.073)^t
Answer: y=390,000(1+0.073)^t
Answer:
72
Step-by-step explanation:
replace the variable of x with 6 in the equation.
<span>Unless you have some other choices, I'd have to say Stratification, to make sure the groups are representative and heterogeneous.
I hope I helped.</span>
College A
13,700 + 1200x = y
College B
26,500 + 400x = y
13,700 + 1,200(16) = 32,900
26,500 + 400(16) = 32,900
The colleges will have the same enrollment after 16 years, in 2019.