Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
Answer:
I think is 2/9 but I may be wrong
A° = 1/2 (90) = 45°
b° = 1/2[360 - (110 + 90)]
b° = 1/2(160)
b° = 80°
a° + b° = 45° + 80° = 135°
Answer
135°
(Sorry if I'm wrong)
Enlarged means making it bigger, so you're making it 3 1/2 times bigger.
Try multiplying both the area and perimeter by 3.5
(6 x 3.5) (8 x 3.5)
P = 21cm and A = 28cm
Answer:
y= 3.99x + 13.99
Step-by-step explanation:
slope intercept is y= mx + b. X is going to be a factor thats going to be multiplied (per month), and in addition to that will be the 13.99 as basically the starting fee.
