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tigry1 [53]
3 years ago
15

A newly planted tree will be secured by wires, each attached to the ground 1.5 meters from the base of the tree. If each wire is

4 meters long, how high up the tree should each wire be attached, to the nearest tenth of a meter?
Mathematics
1 answer:
quester [9]3 years ago
7 0

Answer:

<em>3.7m</em>

Step-by-step explanation:

The set up will form of right angled triangle with;

the length of the wires (the hypotenuse) = 4m

The base of the tree from the wire (adjacent) = 1.5m

The height of the tree(opposite ) = x

According to pythagoras theorem;

<em>hyp² = opp²+adj²</em>

<em>4² = x²+1.5²</em>

<em>16 = x²+2.25</em>

<em>x² = 16 - 2.25</em>

<em>x² = 13.75</em>

<em>x = √13.75</em>

<em>x = 3.708</em>

<em>Hence the tree is 3.7m high (to the nearest tenth)</em>

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Niklas takes a dose of 25 micrograms of a certain supplement each day. The supplement has a half life of 4 hours, meaning that 1
MrRa [10]

Answer:

The amount of the supplement in Niklas' body immediately after the 12th dose is 4.30 micrograms.

Step-by-step explanation:

Half life is the time required for an element to decay into half of its initial size. The supplement has a half life of 4 hours means that it decay to half of its size every 4 hours. Therefore there are 6 stages of division in a day.

i.e     \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} =  \frac{1}{64}

The amount of the supplement in Niklas' body after the first dose (first day) can be determined by;

                   = \frac{1}{64} × 25

                  = 0.390625 micrograms

He used the supplement daily for 12 days (12th dose), but the amount of the supplement in his body immediately after the 12th dose would be;

                 amount in his body per day × number of period for complete decay

                   = 0.390625 × 11

                  = 4.296875

The amount of the supplement in Niklas' body immediately after the 12th dose is 4.30 micrograms. This is because immediately after the 12th dose, the supplement has not reach its half life.

3 0
3 years ago
The distance between -2 1/2 - (-3)
Ierofanga [76]

The distance between -2 1/2 - (-3)​

-2 1/2 + 3

1/2

______________________

Answer

1/2

3 0
1 year ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
The length of a rectangular mailing label is
galben [10]

Let w be the width

Then the length is 2w - 2

We also know that the perimeter is 62 cm. The perimeter is the distance around the rectangle, or 2w + 2(2w - 2).

So, 2w + 2(2w - 2) = 62

2w + 4w - 4 = 62

6w = 66

w = 11

So, the length is 2w - 2 = 2(11) - 2 = 22 - 2 = 20

Length = 20 cm

Width = 11 cm


5 0
3 years ago
Don't mind this thank you :)
Anna007 [38]

Answer:

i will mind this thank you

Step-by-step explanation:

5 0
3 years ago
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