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3 years ago

15

Pls help Thank you.

1 answer:

slamgirl [31]3 years ago

7 0

Answer: A is about 90

Step-by-step explanation: B is 190

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Chloe draws 8 pictures Reggie draws I more picture than Chloe. How many pictures do they draw?

Marat540 [252]

Reggie Would Draw 9 Pictures
And Together They Draw 17

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3 years ago

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Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d

inna [77]

Answer:

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7 0

3 years ago

Plz help I need help I am very confused

KIM [24]

Answer:

$- \frac{5}{7}$

Step-by-step explanation:

$- \frac{2}{7} - \frac{3}{7}$

$\frac{ - 2 - 3}{7}$

$= \frac{ - 5}{7}$

6 0

3 years ago

Prove that if a is equivalent to 5 mod (8) and b is equivalent to 3 mod (8), then 8 divides ab+1

olga nikolaevna [1]

Answer:

Explanation contains the proof.

Step-by-step explanation:

$a \equiv 5 (mod 8) \text{ means there is integer } k \text{ such that } a-5=8k$ .

$b \eqiv 3 (mod 8) \text{ means there is integer } m \text{ such that } b-3=8m$ .

We want to show that $8 \text{ divides } ab+1$ . So we are asked to show that there exist integer $n \text{ such that } 8n=ab+1 \text{ or 8n-1=ab$

So what is $ab$ ?

$a-5=8k \text{ gives us } a=8k+5$ .

$b-5=8m \text{ gives us } b=8m+5$ .

So back to $ab$ ....

$ab$

$=(8k+5)(8m+5)$

$=64km+40k+40m+25$ (I use foil to get this)

Factoring out 8 gives us:

$=8(8km+5k+5m)+25$

Now I could have factored some 8's out of 25. There are actually three 8's in 25 with a remainder of 1.

$=8(8km+5k+5m+3)+1$

We have shown that there is integer $n \text{ such that } ab=8n-1$ .

The integer I found that is n is 8km+5k+5m+3.

Therefore $8|(ab+1)$ .

//

5 0

3 years ago

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A ribbon is 5 2 5 yards long. Mae needs to cut the ribbon into pieces that are 2 5 of a yard long. How many pieces of ribbon can

Rom4ik [11]

Answer: The number of pieces of the ribbon she can cut = $13\frac12$ yards

Step-by-step explanation:

Given: The length of the ribbon = $5\dfrac25$ yards

$= \dfrac{5\times5+2}{5} =\dfrac{27}{5}$ yards

Length of each piece = $\dfrac25$ yards

The number of identical pieces can be cut from the entire ribbon = (Length of the ribbon ) ÷ (Length of each piece )

$=\dfrac{27}{5}\div\dfrac{2}{5}\\\\=\dfrac{27}{5}\times\dfrac{5}{2}\\\\=\dfrac{27}{2}\\\\=13\dfrac12$

Hence, the number of pieces of the ribbon she can cut = $13\frac12$ yards

7 0

2 years ago