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Sonbull [250]
3 years ago
15

Pls help Thank you.​

Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer: A is about 90

Step-by-step explanation: B is 190

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Can someone please help me with this algebra
Novay_Z [31]

Answer: d

Step-by-step explanation:

5 0
3 years ago
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The formula for the area A of a trapezoid is A=1/2(b1+b2)h, where b1 and b2 represents the lengths of the bases and h represents
aleksandr82 [10.1K]

Answer:

B. h=2A/(b1+b2) . . . . parentheses are needed

Step-by-step explanation:

Multiply the equation by the inverse of the coefficient of h. That coefficient is (b1 +b2)/2, so its inverse is 2/(b1 +b2). Parentheses are needed.

... 2A/(b1 +b2) = h

_____

<em>Comment on the answer choices</em>

As written, <em>none of them are correct</em>. The denominator can only be written without parentheses if the division bar is horizontal, and so serves also as a grouping symbol.

6 0
3 years ago
What is 3gh 2 x 4g 3h 3
Alexus [3.1K]

Answer:

(3•22g4h5)

Step-by-step explanation:

Step 1:  ((3gh2 • 4) • g3) • h3

Step 2:   ((3•22gh2) • g3) • h3

Step 3:   3.1 h2 multiplied by h3 = h(2 + 3) = h5

Final answer:   (3•22g4h5)

(IF THIS HELPED PLEASE GIVE BRAINLIEST OR RATE IT 5 STARS!)

5 0
3 years ago
What extra step must be done to solve for x once a polynomial has been factored?
masya89 [10]

Answer:

you  have to set each factor to 0 and solve.

Step-by-step explanation:

6 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
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