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Zielflug [23.3K]
3 years ago
10

Simply the expression 6-2X+5+4x

Mathematics
2 answers:
Lerok [7]3 years ago
4 0

Answer:

2x + 11

I hope this helps!

Alisiya [41]3 years ago
3 0
<h2>Answer:</h2><h2 /><h2>6-2x+5+4x</h2><h2>Add the numbers</h2><h2>11-2x+4x</h2><h2>Combine like terms</h2><h2>Rearrange terms</h2><h2>2x+11</h2>

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Find the mistake. How would you solve this problem correctly? plz answer btw those a minus this is due at 11: 59
garik1379 [7]

Answer:

The mistake is in the second "problem" or the second part

Step-by-step explanation:

solve correctly by using pemdas when there are parenthesis but only "one" number (4) and a variable (x) you multiple (bring over the 6 and times both) leaving you with 6x + 24

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Whats the lmc of 8,28
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Solve the percent proportion. 7 is 35% of what number?
elena55 [62]

Answer:

<u>35</u><u> </u><u>×x</u><u> </u><u>=</u><u>7</u>

100

<u>35x=7</u>

<u>100</u>

<u>35x=700</u>

<u> </u><u> </u><u>35</u><u> </u><u> </u><u> </u><u> </u><u> </u><u>35</u>

<u>x</u><u> </u><u>=</u><u> </u><u>20</u><u>.</u>

<h2><u>HOPE</u><u> </u><u>IT</u><u> </u><u>HELPS,BRAINLIESTPLEASE</u></h2>
3 0
2 years ago
Order the following in ascending order. ​
fomenos
3/8 2/5 0.44 0.5 is the answer d !!
3 0
3 years ago
An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

6 0
3 years ago
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