M=n(pie)/RT
n=osmotic pressure(1.2 atm)
M=molar of the solution
R=gas constant(0.0821)
T= temperature in kelvin 25+273
M=[1.2atm /(0.0821L atm/k mol x 298k)]=0.049mol L
M= moles of the solute/ litres of solution(250/1000)
0.049= y/0.25
moles of solute is therefore =0.01225mol
molar mass=33.29 g/0.01225mol=2.7 x10^3g/mol
Answer:
The final temperature (in degrees Celsius) of the iron block is 85.82 °C
Explanation:
<u>Determine the heat emitted by the condensing water.</u>
qw = 0.88 g H2O
qw = -2.1492 kJ
<u>Determine the heat absorbed by the iron block</u>
qw = - qw = - (-2.1492 kJ) = 2.1492 kJ
<u>Look up the specific heat for iron. Use the specific heat equation to solve for the final temperature of the iron block.</u>
q = mcΔT
ΔT = q / mc
Temp f = (q / mc) + Temp i
Temp f = 2.1492 x 10^3 J / 75 g (0.449 J/g.°C) + 22 °C
Temp f = 85.82 °C
The answer is (3) heat of reaction. The difference in energy between the products and the reactants is the amount of energy either absorbed or liberated during the process (depending on whether the difference is negative or positive).
Answer:
option A is the ans i think so