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tensa zangetsu [6.8K]
1 year ago
14

In the laboratory you dissolve 12.2 g of iron(II) iodide in a volumetric flask and add water to a total volume of 500 mL.

Chemistry
1 answer:
NeTakaya1 year ago
6 0

Answer:

a.) 0.0788 M

b.) 0.0788 M

c.) 0.156 M

Explanation:

To find the molarity of the solution, you need to (1) convert grams FeI₂ to moles FeI₂ (via the molar mass from periodic table) and then (2) calculate the molarity (via the molarity equation using the moles and volume). To find the concentration of each ion, you need to multiply the compound's molarity by the amount of each ion in the molecule.

<u>(Step 1)</u>

Molar Mass (FeI₂): 55.845 g/mol + 2(126.90 g/mol)

Molar Mass (FeI₂): 309.645 g/mol

12.2 g FeI₂              1 mole
------------------  x  ---------------------  =  0.0394 mole FeI₂
                             309.645 g

<u>(Step 2)</u>

500 mL / 1,000 = 0.5 L

Molarity (M) = moles / volume (L)

Molarity = 0.0394 mole / 0.5 L

Molarity = 0.0788 M

<u>(Step 3)</u>

FeI₂ = 1 iron cation and 2 iodide anions

Iron (II) Cation: 1 x 0.0788 M = 0.0788 M

Iodide Anion: 2 x 0.0788 M = 0.156 M

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Luba_88 [7]

Answer:

  • <u>Yes,</u> <em>all titrations of a strong base with a strong acid have the same pH at the equivalence point.</em>

       This <u>pH is 7.</u>

Explanation:

<em>Strong acids</em> and <em>strong bases</em> ionize completely in aqueous solutions. The ionization of strong acids produce hydronium ions, H₃O⁺, and the ionization of strong bases produce hydroxide ions, OH⁻.

Since the ionization of strong acids and bases progress until completion, there is not reverse reaction.

The definition of pH is pH = - log [H₃O⁺]. Acids have low pH (below 7, and greater than 0) and bases have high pH (above 7 and less than 14). Neutral solutions have pH = 7.

Acid-base titrations are a method to determine the concentration of an acid from the known concentration of a base, or the concentraion of a base from the known concentration of an acid.

The<em> equivalence point</em> of the titration is the point at which the the number of moles of hydronium ions and hydroxide ions are equal.

Then, at that point, the hydronium and hydroxide ions will be in the stoichiometric proportion to form a neutral solution, i.e. the pH of the solution wiill be 7.

7 0
3 years ago
If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
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Answer:-

29.07 gram of Cu(NO3)2 will be formed.

4.756 grams of AgNO3 will be left over when the reaction is complete.

Explanation:-

Atomic weight of Cu = 63.546 g mol -1

Molecular weight of AgNO3 = 107.87 x 1 + 14 x 1 + 16 x 3

= 169.87 g mol-1

Number of moles of Copper = 9.85 gram / (63.546 g mol-1)

= 0.155 mol

Number of moles of AgNO3 = 31 gram / ( 169.87 g mol-1)

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The balanced chemical equation for this reaction is

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According to the equation,

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∴0.155 mol of Cu react with 0.155 mol of AgNO3.

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1 Cu gives 1 Cu(NO3)2

∴ 63.546 g of Cu gives 187.546 gram of Cu(NO3)2

9.85 grams pf Cu gives 187.546 x 9.85 / 64.546 gram of Cu(NO3)2

= 29.07 gram of Cu(NO3)2

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